programmers 주차 요금 계산

https://school.programmers.co.kr/learn/courses/30/lessons/92341

프로그래머스

---

import math
def solution(fees, records):
    inout = {}
    arr = []
    for i in range(len(records)):
        information = records[i].split()
        inout[information[1]] = 0

    for i in range(len(records)):
        information = records[i].split()
        Time = int((information[0][0]) + (information[0][1]))*60 + int(information[0][3] + information[0][4])
        if information[2] =='IN':
            inout[information[1]] = [Time,'IN']
        if information[2] =='OUT':
            out=[(Time - inout[information[1]][0]), 'OUT']
            inout[information[1]] = out
            arr.append((information[1],out))
            
    for i in (inout):

        if inout[i][1] == 'IN':
            inout[i][0]=1439- inout[i][0]
            arr.append((i,inout[i]))
    # dict를 sort시키는 법
    arr.sort()

    dic = {}
    for i in range(len(arr)):
        dic[arr[i][0]] = 0
    for i in range(len(arr)):
        dic[arr[i][0]] += arr[i][1][0]
    arr3 = []
    for i in dic:
        if dic[i] <= fees[0]:
            arr3.append(fees[1])
        else:
            arr3.append(fees[1]+(math.ceil((dic[i] - fees[0])/fees[2]))*fees[3])

    return arr3